Two identical organ pipes are producing fundamental notes of frequency 200 Hz at 15- C- If the temperature of one pipe is raised to 27- C- the number of beats produced will be

The correct option is C 4 f = v/λ f = 0.6×12 = 7.2 ms^ 1 λ = 340/200 = 1.7 ∴ f = 4(nearly) ...

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Standard XII

Physics

Standing Waves in Closed Organ Pipe

Two identical...

Question

Two identical organ pipes are producing fundamental notes of frequency $200 H z$ at $15^{\circ} C$ . If the temperature of one pipe is raised to $27^{\circ} C$ , the number of beats produced will be

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Solution

The correct option is C $4$
$△ f = \frac{△ v}{λ} △ f = 0.6 \times 12 = 7 .2 m s^{- 1}$
$λ = \frac{340}{200} = 1.7 ∴ △ f = 4 (n e a r l y)$

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Two identical organ pipes are producing fundamental notes of frequency 200 Hz at 15∘ C. If the temperature of one pipe is raised to 27∘ C, the number of beats produced will be

The correct option is C 4△f=△vλ△f=0.6×12=7.2 ms−1λ=340200=1.7∴△f=4 (nearly)

Two identical organ pipes are producing fundamental notes of frequency $200 H z$ at $15^{\circ} C$ . If the temperature of one pipe is raised to $27^{\circ} C$ , the number of beats produced will be

The correct option is C $4$
$△ f = \frac{△ v}{λ} △ f = 0.6 \times 12 = 7 .2 m s^{- 1}$
$λ = \frac{340}{200} = 1.7 ∴ △ f = 4 (n e a r l y)$