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Question

Two identical parallel plate capacitance C each are connected in series with a battery of emf, E as shown, If one of the capacitors is now filled with a dielectric of dielectric constant k, the amount of charge which will flow through the battery is ?(neglect internal resistance of the battery)
632590_b5aa11b24d7f46a199979a83d5b55434.jpg

A
k+12(k1)CE
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B
k12(k+1)CE
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C
k2k+2CE
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D
k+2k2CE
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Solution

The correct option is B k12(k+1)CE
Inital charge on both the capacitor Q=CE2
final chargeQf=kCEK+1
charge flow from batter is QfQ=k12(k+1)CE

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