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Question

Two identical parallel plate capacitors of capacitance C each are connected in series with a battery of Emf, E as shown. If one of the capacitors is now filled with dielectric constant k, the amount of charge which will flow through the battery is

A
(k+1)2(k1)CE
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B
(k1)2(k+1)CE
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C
k2k+2CE
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D
(k+2)(k2)CE
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Solution

The correct option is B (k1)2(k+1)CE
Q1=(C2)E
Q2=kk+1CE
ΔQ=Q2Q1
=kCEk+1C2E
=CE(k12(k+1))

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