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Question

Two identical particles A and B, each of mass m, are interconnected by a spring of stiffness k. If particle B experiences a force F and the elongation of the spring is x, the acceleration of particle B relative to particle A is equal to


A

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B

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C

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D

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Solution

The correct option is C


Equation of motion for A (Fig),

Kx = ma a=kxm

For B:F - T = ma'

a=Fkxm

Thus, relative acceleration = ar=|aa|=F2kxm


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