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Question

Two identical rods each of mass 'M' and length 'l' are joined in crossed position. The moment of inertia of this system about a bisector is.

A
Ml26
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B
Ml212
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C
Ml23
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D
Ml24
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Solution

The correct option is B Ml212
Moment of inertia of system about an axes which is perpendicular to plane of rods and passing through the common centre of rods Iz=Ml212+Ml212=Ml26
Again from perpendicular axes theorem I2=IB1+IB2=2IB1=2IB2=Ml26 [As IB1=IB2]
IB1=IB2=Ml212.

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