Two identical rods of a mental are welded in series then 20 cal of heat flows through them in 4 minute. If the rods are welded in parallel then same amount of heat will flow in
dq/dt=[(AK)/2x][T2−T1]=20/4=5.
Therefore(AK/x)(T2−T1)=10
When they are one above the other,
dq/dt=2Ak/x][T2−T1]=20/t
Thereforet=2×10=20/t
Thereforet=1min