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Standard XII

Physics

Thermal Expansion

Two identical...

Question

Two identical rods of length $L$ each are connected together as shown in figure. Temperature of 3 ends are given, then temperature $θ$ of junction is

54.2

^{\circ} C

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36.8

^{\circ} C

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^{\circ} C

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^{\circ} C

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Solution

The correct option is B 36.8 $^{\circ} C$

$i_{1} + i_{2} = i_{3}$

$\frac{4 K A (100 - θ)}{3 L} + \frac{K A (60 - θ)}{L} = \frac{4 K A (θ - 10)}{L}$

$\frac{400}{3} - \frac{4 θ}{3} + 60 - θ = 4 θ - 40$

$\Rightarrow θ = 36.8^{\circ} C$

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Two identical rods of length L each are connected together as shown in figure. Temperature of 3 ends are given, then temperature θ of junction is

The correct option is B 36.8 ∘C i1+i2=i3 4KA(100−θ)3L+KA(60−θ)L=4KA(θ−10)L 4003−4θ3+60−θ=4θ−40 ⇒θ=36.8 ∘C

Two identical rods of length $L$ each are connected together as shown in figure. Temperature of 3 ends are given, then temperature $θ$ of junction is

The correct option is B 36.8 $^{\circ} C$

$i_{1} + i_{2} = i_{3}$

$\frac{4 K A (100 - θ)}{3 L} + \frac{K A (60 - θ)}{L} = \frac{4 K A (θ - 10)}{L}$

$\frac{400}{3} - \frac{4 θ}{3} + 60 - θ = 4 θ - 40$

$\Rightarrow θ = 36.8^{\circ} C$