Two identical sphere of radii 10 cm each are placed in between two rigid walls (vertical) as shown .The soacing between the walls is 36 cm.Then find of contact between thee sphere ,if the weight of each sphere is W is
Two identical uniform frictionless spheres, each of weight W, rest as shown in Fig. at the bottom of a fixed, rectangular container. The line of centres of the spheres makes an angle 0 with the horizontal
The sphere at the top is in vertical equilibrium, therefore
N.sinϴ = W
N = W/sinϴ You can calculate sinϴ from figure. sinϴ=3/5
Contact forces between two spheres will be 5/3 W