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Question

Two identical spheres having charges +q1 and +q2 are kept at a distance "d". These two are brought in contact with an insulated handle and again separated to the same distance. Find the force F2 between them in terms of initial force F1.

A
F2=F1(q1+q2)34q21q2
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B
F2=F1(q1+q2)34q1q22
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C
F2=F1(q1+q2)4q1
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D
F2=F1(q1+q2)24q1q2
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Solution

The correct option is D F2=F1(q1+q2)24q1q2
Let initially, charges are separated by a distance d.
Then, according to Coulomb's Law,
F1=kq1q2d2
d2=kq1q2F1 ...(i)

Now, when both the identical spheres are brought in contact, then charge on each sphere is average of initial charge on each sphere.
i.e, Q=q1+q22 on each sphere.

Now, Force between them i.e, F2 is
F2=kQ2d2
From (i), d2=kq1q2F1
So, F2=k(q1+q2)2kq1q2×4×F1
F2=F1×(q1+q2)24q1q2

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