Question

Two identical spring of constant K are connected in series and parallel as shown in figure. A mass m is suspended from them. The ratio of their frequencies of vertical oscillations will be

• A. 2:1
• B. 1:1
• C. 1:2
• D. 4:1

Answer 1

The correct option is C

1:2

n = $\frac{1}{2\pi }\sqrt{\frac{k}{m}}\Rightarrow \frac{n_S}{n_P}=\sqrt{\frac{k_S}{k_P}}\Rightarrow \frac{n_s}{n_p}=\sqrt{\frac{\left(\frac{k}{2}\right)}{2k}}=\frac{1}{2}$