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Question

Two identical springs of spring constant k are attached to a block of mass m and to fixed support. Show that when the mass is displaced from its equilibrium position then either side,it executes a simple harmonic motion. Find the period of oscillation.

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Solution

Dear student,If we displace the mass in any direction, the other spring will pull it back due to restoring force. The force if F=-kxon the other hand F=mf from newtons second law therefore mf=-kx f=-kmxthis is a representation of SHM where acceleration is proportional to the displacement.and the frequency ω=kmif period of oscillation is Tthen ω=2πT=km T= 2πkm
Regards

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