Question

Two identical thin rings, each of radius $R$ metres, are coaxially placed a distance $R$ metres apart. If $Q_1$ coil and $Q_2$ coil are respectively the charges uniformly spread on the two rings, the work is done in moving a charge $q$ form the centre of one ring to that of the other is?

• A. $Q_1-Q_2(\frac{1}{\sqrt{R^2=r^2}}-\frac{1}{r})$
• B. $\frac{q(Q_1-Q_2)(\sqrt{2}-1)}{\left(\sqrt{2.4}\pi {\epsilon }_{0}R\right)}$
• C. $\frac{q\sqrt{2}(Q_1-(+Q_2\left)\right)}{\left(4\pi {\epsilon }_{0}R\right)}$
• D. $\frac{q(Q_1-(+Q_2\left)\right)(\sqrt{2}-1)}{\left(\sqrt{32}\pi {\epsilon }_{0}R\right)}$

Answer 1

The correct option is D $\frac{q(Q_1-(+Q_2\left)\right)(\sqrt{2}-1)}{\left(\sqrt{32}\pi {\epsilon }_{0}R\right)}$