Two identical triangular wave pulses whose centres are initially 4cm apart, have been shown in figure given below. The speed of each pulse is 1cm/s. After 2second, the shape of resultant wave-pulse will be
A
Triangular
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B
Rectangular
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C
Straight line
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D
None of these.
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Solution
The correct option is C Straight line ⇒considering t=0 for the initial shape of pulses on the string.
After t=2s, the displacement of centre of one pulse w.r.t another pulse: Δx=(v1+v2)t=2×2=4cm
The figure given below represents the snapshot of wave-pulses on string at t=2s
The displacement of particles is equal but in opposite direction, corresponding to each wave pulse. ⇒Hence on superposition, it will result the zero displacement of particles on string from their mean position. ∴Shape of resultant pulse will be a straight line.