Two identical trusses support a load of 100 N as shown in the figure. The length of each truss is 1.0 m, cross - sectional area is 200 mm^2; Young's modulus E = 200 GPa. The force in the truss AB (in N) is

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Solution

$\frac{F_{A B}}{sin 120^{\circ}} = \frac{100}{sin 120^{\circ}} o r F_{A B} = 100 N$

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Two identical trusses support a load of 100 N as shown in the figure. The length of each truss is 1.0 m, cross - sectional area is 200 mm^2; Young's modulus E = 200 GPa. The force in the truss AB (in N) is

FABsin120∘=100sin120∘orFAB=100N

$\frac{F_{A B}}{sin 120^{\circ}} = \frac{100}{sin 120^{\circ}} o r F_{A B} = 100 N$