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Question

Two immiscible liquid of densities ρ1 and ρ2 are in equilibrium by forming a slant interface. The angle of inclination θ of the interface of the liquids is:

A
0.0
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B
tan1ρ1 + ρ2ρ1 ρ2
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C
tan1ρ1 ρ2
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D
tan1ρ2ρ1
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Solution

The correct option is A 0.0
If the liquids are at rest, the interface is essentially horizontal. So θ= 0.

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