Two immiscible liquid of densities ρ1 and ρ2 are in equilibrium by forming a slant interface. The angle of inclination θ of the interface of the liquids is:
A
0.0
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B
tan−1ρ1+ρ2ρ1−ρ2
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C
tan−1ρ1ρ2
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D
tan−1ρ2ρ1
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Solution
The correct option is A 0.0 If the liquids are at rest, the interface is essentially horizontal. So θ=0.