Question

Two immiscible liquid of densities ${\rho }_1$ and ${\rho }_2$ are in equilibrium by forming a slant interface. The angle of inclination $\theta$ of the interface of the liquids is:

• A. \N
• B. ${\tan }^{-1}\frac{{\rho }_1+{\rho }_2}{{\rho }_1-{\rho }_2}$
• C. ${\tan }^{-1}\frac{{\rho }_1}{{\rho }_2}$
• D. ${\tan }^{-1}\frac{{\rho }_2}{{\rho }_1}$

Answer 1

The correct option is A \N

If the liquids are at rest, the interface is essentially horizontal. So $\theta =0.$