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Net Force

Two individua...

Question

Two individual forces of magnitude $F_{1}$ and $F_{2}$ , act on a body of mass 1 kg as shown in the figures (i) and (ii). If product of net magnitudes of forces produced in fig (i) and (ii) is 27N, then find the magnitude of forces $F_{1}$ , and $F_{2}$ . (assume $F_{1} > F_{2}$ )

6N, 3N

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4N, 8N

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7N, 14N`

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None of the above

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Solution

The correct option is A 6N, 3N
$F_{n e t} (i) = F_{1}^i - F_{2}^i$
$F_{n e t} (i i) = F_{1}^i + F_{2}^i$
$F_{n e t} (i) * F_{n e t} (i i) = (F_{1} - F_{2}) (F_{1} + F_{2})$
$F_{1}^{2} - F_{2}^{2} = 27 N \to (i)$
Any combination is possible such that it staisfies
Let $F_{2} = 3$
$F_{1} = 6$
Hence 6N,3N

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Two individual forces of magnitude F1 and F2, act on a body of mass 1 kg as shown in the figures (i) and (ii). If product of net magnitudes of forces produced in fig (i) and (ii) is 27N, then find the magnitude of forces F1, and F2. (assume F1>F2)

The correct option is A 6N, 3NFnet(i)=F1^i−F2^iFnet(ii)=F1^i+F2^i Fnet(i)∗Fnet(ii)=(F1−F2)(F1+F2)F21−F22=27N→(i)Any combination is possible such that it staisfies Let F2=3 F1=6Hence 6N,3N

Two individual forces of magnitude $F_{1}$ and $F_{2}$ , act on a body of mass 1 kg as shown in the figures (i) and (ii). If product of net magnitudes of forces produced in fig (i) and (ii) is 27N, then find the magnitude of forces $F_{1}$ , and $F_{2}$ . (assume $F_{1} > F_{2}$ )