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Question

Two inductances connected in parallel are equivalent to a single inductance of 1.5 H and when connected in series are equivalent to a single inductance of 8 H. The difference in their inductance is-

A
3 H
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B
7.5 H
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C
2 H
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D
4 H
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Solution

The correct option is D 4 H
Let, L1 and L2 be the individual inductors,

When, L1 and L2 are connected in parallel, their equivalent inductance is,

L1L2L1+L2=1.5 ........(1)

When, L1 and L2 are connected in series, their equivalent inductance is,

L1+L2=8 .........(2)

From (1) and (2) we get,

L1L2=12

And, we can write,

(L1L2)2=(L1+L2)24L1L2

=(8)24×12=6448=16

L1L2=4 H

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.


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