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Question

Two inductors of inductance 2 mH and 5 mH are connected in parallel and a time varying current i flows as shown in the figure. The ratio of currents i1 and i2 at any time t is-


A
2:5
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B
5:2
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C
2:7
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D
4:9
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Solution

The correct option is B 5:2

Potential difference across an inductor is,

|E|=L(didt)

Since, inductors are connected in parallel, hence potential difference across them will be the same.

|E1|=|E2|

2di1dt=5di2dt

2di1=5di2

Integrating both sides with proper limits we get,

i102di1=i205di2

2i1=5i2

i1:i2=5:2

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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