Two inductors of inductance 2mH and 5mH are connected in parallel and a time varying current i flows as shown in the figure. The ratio of currents i1 and i2 at any time t is-
A
2:5
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B
5:2
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C
2:7
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D
4:9
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Solution
The correct option is B5:2
Potential difference across an inductor is,
|E|=L(didt)
Since, inductors are connected in parallel, hence potential difference across them will be the same.
|E1|=|E2|
2di1dt=5di2dt
⇒2di1=5di2
Integrating both sides with proper limits we get,
∫i102di1=∫i205di2
⇒2i1=5i2
∴i1:i2=5:2
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Hence, (B) is the correct answer.