Two infinite length wires carries currents 8A and 6A respectively and placed along X and Y-axis. Magnetic field at a point P(0,0,d)m will be
Magnetic field due to P due to wire 1, B1=μ04π.2(8)d
and due to wire 2, B2=μ04π.2(6)d
⇒ Bnet=√B21+B22
=√(μ04π.16d)2+(μ04π.12d)2
=μ04π×2d×10=5μ0πd