Energy loss in charge redistribution
Loss of energy \(=\dfrac{1}{2}\dfrac{C_1C_2}{C_1+C_2} (V_1−V_2)^2\)
here, \(\dfrac{C_1C_2}{C_1+C_2}=\dfrac{3\times10^{−6}F\times5\times10^{−6}F}{(3+5) (10^{−6})F}\)
\(=\dfrac{15}{8}\times10^{−6}F\)
Loss of energy \(=\dfrac{1}{2}\times\dfrac{15}{8}\times10^{−6}F\times(500 V−300 V)^2\)
\(=\dfrac{15}{4}\times10^{−2}\)
\(= 0.0375 J\)
Thus, energy lost is \(0.0375 J\)