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Question

Two insulating plates are uniformly charged in such a way that potential difference between them is V2 V1 = 20 V. Plates are separated by d=0.1 m. An electron is released from rest in between the plates from the surface of plate 1. What is its speed when it hits the plate 2?
(Charge on an electron, e=1.6×1019 C and mass of an electron, me=9.1×1031 kg)


A
32×1019 m/s
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B
2.65×106 m/s
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C
7.02×1012 m/s
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D
1.87×106 m/s
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Solution

The correct option is B 2.65×106 m/s
Given that,
Potential difference between plates, ΔV=V2V1=20 V
Distance between the plates, d=0.1 m
Charge of an electron, e=1.6×1019 C
Mass of an electron, me=9.1×1031 kg

Let v is the velocity of the electron when it hits plate 2.

By law of conservation of mechanical energy,
Gain in kinetic energy = Loss in potential energy.
12mv2 = e(V2V1)

v = 2e(V2V1)m
v= 2×1.6×1019×209.1×1031
v = 2.65×106 m/s

Hence, option (b) is correct.

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