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Two ions A+...

Question

Two ions $A^{+}$ and $B^{-}$ have radii 88 and 200 pm respectively. In the closed packed crystal of compound predict the co-ordination number of $A^{+}$

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Solution

$\frac{r_{+}}{r_{-}} = \frac{r (A^{+})}{r (B^{-})} = \frac{88 p m}{200 p m} = 0.44$

It lies in the range $0.414$ to $0.732$
Hence, the coordination number of $A^{+} = 6$ .

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Two ions A+ and B− have radii 88 and 200 pm respectively. In the closed packed crystal of compound predict the co-ordination number of A+

r+r−=r(A+)r(B−)=88pm200pm=0.44It lies in the range 0.414 to 0.732Hence, the coordination number of A+=6.

Two ions $A^{+}$ and $B^{-}$ have radii 88 and 200 pm respectively. In the closed packed crystal of compound predict the co-ordination number of $A^{+}$

$\frac{r_{+}}{r_{-}} = \frac{r (A^{+})}{r (B^{-})} = \frac{88 p m}{200 p m} = 0.44$

It lies in the range $0.414$ to $0.732$
Hence, the coordination number of $A^{+} = 6$ .