Question

Two isolated metallic solid sphere of radius R and 2R are charged such that both of these have same charge density a . the spheres are locted far away from each other and are connected by a thin conducting wire . the new charge density on the bigger sphere is

• A. $\frac{5\sigma }{6}$
• B. $\frac{56\sigma }{5}$
• C. $\frac{3\sigma }{5}$
• D. $\frac{52\sigma }{6}$

Answer 1

The correct option is A $\frac{5\sigma }{6}$

Radius $=R$ and $2R$

Charge density $=\sigma$

The surface charge density will remain the same since the small sphere is not kept inside the bigger sphere and hence the charges can not flow in the given situation.

next we have,

${\sigma }_1=\frac{1}{(2R+R)2}\times 5\sigma =\frac{5\sigma }{6}$