Question

Two isosceles triangles have congruent base angles.

The lengths of a leg and base of one triangle are $17cm$ and $10cm$ respectively.

The length of the base of the other triangle is $8cm$.

What is the length of the leg of the second triangle ?

Answer 1

Finding the length of the leg of the second triangle:

When two triangles are congruent, their corresponding side ratio are equal to each other so, here ratio of leg side to base side of one triangle will be equal to ratio of leg side to base side of second triangle.

Let ‘$x$’ be the length of leg of second triangle then ratio of leg side to base side of both triangle will be

$\frac{17}{10}=\frac{x}{8}$

Solving for ‘$x$’ we get

$$\begin{gathered} x=\frac{17\times 8}{10} \\ x=12.6cm \end{gathered}$$

Hence, the length of the leg of second triangle is $12.6cm$