Given: Two isosceles triangles have equal vertical angles and their areas are in the ratio of 16:25.
To find: Ratio of their corresponding heights.
Let ∆ABC and ∆PQR be two isosceles triangles such that . Suppose AD ⊥ BC and PS ⊥ QR .
In ∆ABC and ∆PQR,
We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding altitudes.
Hence,
Hence we got the result as