Question

Two isosceles triangles have equal vertical angles and their areas are in the ratio 36 : 25 . Find the ratio of their corresponding heights.

Answer 1

We know that, for an isosceles $\Delta$

$\frac{ar1}{ar2}=\frac{h_1^2}{h_2^2}$

$=\frac{36}{25}$

$\therefore \frac{h_1}{h_2}=\sqrt{\frac{36}{25}}$

$=\frac{6}{5}$

$\therefore$ Ratio of corresponding heights $=6:5$