Two isotopes of an element X are present in 1:2 ratio having mass number M and (M+0.5) respectively. The mean mass number of X is:

M + \frac{2}{3}

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M + \frac{1}{3}

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M + \frac{1}{4}

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M + 3

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Solution

The correct option is B $M + \frac{1}{3}$
The ratio of two isotopes = $1 : 2$

mass number ratio = $M : M + 0.5$

therefore mean mass number = $\frac{M \times 1 + 2 \times (M + 0.5)}{1 + 2} = M + \frac{1}{3}$

So, the correct option is $B$

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Similar questions

Q. Two isotopes of an element X are present in the ratio of 1:2, having mass number M and (M+0.5) respectively. Find the mean mass number of X.

Q. Three isotopes of an element have mass numbers,

M

(M + 1)

and

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(M + 0.5)

then which of the following ratios may be accepted for

M

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in that order?

Three isotopes of an element have mass number m, (m+1) and (m+2) .if the mass number is (m+0.5) then which of the following ratios may be accepted for m, (m+1),(m+2) in that order

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and

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x =

0 m

and

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If the mean of $x$ and $\frac{1}{x}$ is M, the mean of $x^{3}$ and $\frac{1}{x^{3}}$ is

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Two isotopes of an element X are present in 1:2 ratio having mass number M and (M+0.5) respectively. The mean mass number of X is:

The correct option is B M+13The ratio of two isotopes = 1:2mass number ratio = M:M+0.5therefore mean mass number = M×1+2×(M+0.5)1+2=M+13So, the correct option is B

The correct option is B $M + \frac{1}{3}$
The ratio of two isotopes = $1 : 2$

mass number ratio = $M : M + 0.5$

therefore mean mass number = $\frac{M \times 1 + 2 \times (M + 0.5)}{1 + 2} = M + \frac{1}{3}$

So, the correct option is $B$