Two isotopes of an element X are present in the ratio of 1:2, having mass number M and (M+0.5) respectively. Find the mean mass number of X.

M + \frac{2}{3}

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M + \frac{1}{3}

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M + \frac{1}{4}

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M + 3

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Solution

The correct option is B $M + \frac{1}{3}$
Mean Mass number is the average mass of all isotopes.

So, Mean Mass Number $= \frac{1 \times M + (M + 0.5) \times 2}{1 + 2} = M + \frac{1}{3}$

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Similar questions

Q. Two isotopes of an element X are present in 1:2 ratio having mass number M and (M+0.5) respectively. The mean mass number of X is:

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Two isotopes of an element X are present in the ratio of 1:2, having mass number M and (M+0.5) respectively. Find the mean mass number of X.

The correct option is B M+13Mean Mass number is the average mass of all isotopes.So, Mean Mass Number =1×M +(M+0.5)×21+2=M+13

The correct option is B $M + \frac{1}{3}$
Mean Mass number is the average mass of all isotopes.

So, Mean Mass Number $= \frac{1 \times M + (M + 0.5) \times 2}{1 + 2} = M + \frac{1}{3}$