Two kg of water is converted into steam by boiling at atmospheric pressure- The volume changes from 2 - 10-3 m 3 to 3-34 m 3 The work done by the system is aboutA- 170 KJB- 340 KJC- -340 KJD- -170 KJ

The correct option is B 340 KJ W = P V = 1.01 × 10^5 (3.34 2 × 10^ 3) = 337 × 10^3 J ≈ 340 KJ ...

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Standard XII

Chemistry

Heat of Reaction

Two kg of wat...

Question

Two kg of water is converted into steam by boiling at atmospheric pressure. The volume changes from $2 \times 10^{- 3} m^{3}$ to $3.34 m^{3}$ The work done by the system is about

-340 KJ

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-170 KJ

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170 KJ

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340 KJ

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Solution

The correct option is D
340 KJ

$W = P △ V = 1.01 \times 10^{5} (3.34 - 2 \times 10^{- 3})$

= $337 \times 10^{3} J \approx 340 K J$

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Two kg of water is converted into steam by boiling at atmospheric pressure. The volume changes from 2×10−3m3 to 3.34m3 The work done by the system is about

The correct option is D 340 KJ W=P△V=1.01×105(3.34−2×10−3) = 337×103J≈340KJ

Two kg of water is converted into steam by boiling at atmospheric pressure. The volume changes from $2 \times 10^{- 3} m^{3}$ to $3.34 m^{3}$ The work done by the system is about

The correct option is D
340 KJ

$W = P △ V = 1.01 \times 10^{5} (3.34 - 2 \times 10^{- 3})$

= $337 \times 10^{3} J \approx 340 K J$