Two large glass plates are placed vertically and parallel to each other inside a tank of water with separation between the plates equal to $1$ mm. Find the rise of water in the space between the plates. Surface tension of water $= 0.075 N m^{- 1}$ .

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Solution

surface tension of water $T = 0.075 n m$

separation of glass plate d is 1mm $10^{- 3} m$

density of water is $10^{3} k g / m^{3}$

$h = \frac{2 \times 0.075}{10^{- 3} \times 10^{3} \times 10} = 0.015 m = 1.5 c m$

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Two large glass plates are placed vertically and parallel to each other inside a tank of water with separation between the plates equal to 1mm. Find the rise of water in the space between the plates. Surface tension of water =0.075Nm−1.

surface tension of water T=0.075nmseparation of glass plate d is 1mm 10−3mdensity of water is 103kg/m3h=2×0.07510−3×103×10=0.015m=1.5cm

Two large glass plates are placed vertically and parallel to each other inside a tank of water with separation between the plates equal to $1$ mm. Find the rise of water in the space between the plates. Surface tension of water $= 0.075 N m^{- 1}$ .

surface tension of water $T = 0.075 n m$

separation of glass plate d is 1mm $10^{- 3} m$

density of water is $10^{3} k g / m^{3}$

$h = \frac{2 \times 0.075}{10^{- 3} \times 10^{3} \times 10} = 0.015 m = 1.5 c m$