Two large plates are given the charges as shown in the figure. The left plate is now earthed. The amount of charge that will flow from earth to this plate is
A
14μC
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B
−14μC
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C
7μC
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D
−7μC
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Solution
The correct option is B−14μC Given, initial charge on left plate, qi=10μC
Since the final charges on the outer surfaces of both the plates should be =0.
The charges on inner surface of right plate =(4−0)=4μC
So, the final charge on inner surface of left plate, qf=−4μC
Thus, charge flow from the earth=qf−qi=−4−10=−14μC