Question

Two legs of a right triangle are $8\sqrt{\pi }$ and $9\sqrt{\pi }$ as shown A circle is drawn so that the area inside the circle but outside the triangle equals the area inside the triangle but outside the circle The radius of the circle is (Use $\pi =22/7$)

• A. $6\sqrt{\pi }$
• B. $6$
• C. $5$
• D. $8$

Answer 1

The correct option is B $6$

Given: Area inside the circle but outside the triangle equals the area inside the triangle but outside the circle
If area both inside the circle and the triangle are added, then
area of triangle = area of circle
$\frac{1}{2}\left(8\sqrt{\pi }\right)\left(9\sqrt{\pi }\right)=\pi r^2$
$36\pi =\pi r^2$
$r=6$ cm