Two lenses of power 10D and −10D are in contact, find power, focal length and nature of lens combination.
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Solution
Given : P1=10D and P2=−10D Power of combination of lenses Pnet=P1+P2 ∴Pnet=10−10=0D Focal length of combination of lenses Fnet=1Pnet=10=∞ Since focal length of plane lens is infinite. So above combination of lens becomes a plane lens.