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Standard X

Physics

Nuclear Fusion

Two light nuc...

Question

Two light nuclei of masses $m_{1}$ and $m_{2}$ are fused to form a more stable nucleus of mass $m_{3}$ then :-

m_{3} = | m_{1} - m_{2} |

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m_{3} < (m_{1} + m_{2})

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m_{3} > (m_{1} - m_{2})

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m_{3} = | m_{1} + m_{2} |

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Solution

The correct option is B $m_{3} < (m_{1} + m_{2})$
When two nuclei of masses $m_{1}$ and $m_{2}$ are fused to form a stable nucleus of mass $m_{3}$ and some of the mass is converted in energy.

Therefore,

$m_{3} < m_{1} + m_{2}$

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Two light nuclei of masses m1 and m2 are fused to form a more stable nucleus of mass m3 then :-

The correct option is B m3<(m1+m2)When two nuclei of masses m1 and m2 are fused to form a stable nucleus of mass m3 and some of the mass is converted in energy. Therefore, m3<m1+m2

Two light nuclei of masses $m_{1}$ and $m_{2}$ are fused to form a more stable nucleus of mass $m_{3}$ then :-

The correct option is B $m_{3} < (m_{1} + m_{2})$
When two nuclei of masses $m_{1}$ and $m_{2}$ are fused to form a stable nucleus of mass $m_{3}$ and some of the mass is converted in energy.

Therefore,

$m_{3} < m_{1} + m_{2}$