Question

Two light strings of length 4 cm and 3cm are tied to a bob of weight 500gm. The free ends of the strings are tied to pegs in the same horizontal line and separated by 5cm. The ratio of tension in the longer string to that in the shorter string is:

• A. 4 : 3
• B. 3 : 4
• C. 4 : 5
• D. 5 : 4

Answer 1

Answer: (B)

3 : 4

A figure has been attached with the solution for better clarification.

Let the two pegs be 'B' and 'C' and the bob be at 'A'

Let the tensions in the two strings be $T_{1}and{T}_2$

Writing the force equation in horizontal direction we have

$T_1\cos \theta =T_2\sin \theta \Rightarrow T_1/T_2=\cot \theta =3/4⟶(Fromthefig.)$