Two like charged, infinitely long parallel wires with linear charge density of $3 \times 10^{- 8}$ C/cm are 2 cm apart. The work done against electrostatic force per unit length to be done in bringing them closer by 1 cm is $\frac{x}{10} J / m$ . Find the integer closest to x. ___

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Solution

$W = q Δ V$
$= (λ l) (2 K λ I n (\frac{r_{B}}{r_{A}})]$
$= (3 \times 10^{- 8} \times 100) [2 \times 9 \times 10^{9} \times 3 \times 10^{- 6} I n 2]$
$= 112.3 \times 10^{- 3} J / m$
$= \frac{1.12}{10} J / m$

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Two like charged, infinitely long parallel wires with linear charge density of 3×10–8 C/cm are 2 cm apart. The work done against electrostatic force per unit length to be done in bringing them closer by 1 cm is x10J/m . Find the integer closest to x. ___

W=qΔV =(λl)(2KλIn(rBrA)] =(3×10−8×100)[2×9×109×3×10−6In2] =112.3×10−3J/m =1.1210J/m

Two like charged, infinitely long parallel wires with linear charge density of $3 \times 10^{- 8}$ C/cm are 2 cm apart. The work done against electrostatic force per unit length to be done in bringing them closer by 1 cm is $\frac{x}{10} J / m$ . Find the integer closest to x. ___

$W = q Δ V$
$= (λ l) (2 K λ I n (\frac{r_{B}}{r_{A}})]$
$= (3 \times 10^{- 8} \times 100) [2 \times 9 \times 10^{9} \times 3 \times 10^{- 6} I n 2]$
$= 112.3 \times 10^{- 3} J / m$
$= \frac{1.12}{10} J / m$