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Question

Two lines are drawn through the point (1, 3) one of slope and the other of slope −2. Write the coordinates of one more point on each of these lines. Prove that these lines are perpendicular to each other.

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Solution

Let the given point be A (1, 3).

Let the point B (x, y) lie on the line passing through point A.

Given that the slope of the first line passing through point A is

2y 6 = x 1

x 2y + 5 = 0

This is the equation of the line passing through point A and having slope

Any point on this line can be found out by assuming x to have any value, say 2 and putting it in the above equation.

2 2y + 5 = 0

⇒ −2y + 7 = 0

y =

Thus, the coordinates of one more point on the first line are

Also, given that the slope of the second line passing through point A is 2.

y 3 = 2x + 2

2x + y 5 = 0

This is the equation of the line passing through point A and having slope 2.

Any point on this line can be found out by assuming x to have any value, say 2 and putting it in the above equation.

4 + y 5 = 0

y 1 = 0

y = 1

Thus, the coordinates of one more point on the second line are (2, 1).

Let m1 = , m2 = 2

For two lines to be perpendicular, the product of their slopes should be equal to 1.

m1 m2 = × (2) = 1

Therefore, the given lines are perpendicular to each other.


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