Two lines are given by (x−2y)2+k(x−2y)=0.The value of k so that the distance between them is 3, is
None of these
Applying the formula, the distance between them is ∣∣ ∣∣2√(k24)−01.(1+4)∣∣ ∣∣=|k√5|,
∴|k√5|=3⇒k=±3√5