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Question

Two lines are given by (x2y)2+k(x2y)=0.The value of k so that the distance between them is 3, is


A

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B

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C

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D

None of these

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Solution

The correct option is C


Applying the formula, the distance between them is ∣ ∣2(k24)01.(1+4)∣ ∣=|k5|,

|k5|=3k=±35


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