Two lines intersect at a point and a ray is drawn from the point of intersection. The ray divides the angle between the lines into 1:2 ratio. One of the angles is given, find the value of 'x'.

$100^{\circ}$

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$60^{\circ}$

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$30^{\circ}$

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$50^{\circ}$

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Solution

The correct option is D
$50^{\circ}$

From the diagram, $30^{\circ}$ , 1x and 2x all lie on one the same side of the 'line 2',

So, sum of all three angles is $180^{\circ}$

or, $30^{\circ}$ +x +2x = $180^{\circ}$

or, 3x = $150^{\circ}$

or, x = $50^{\circ}$

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Two lines intersect at a point and a ray is drawn from the point of intersection. The ray divides the angle between the lines into 1:2 ratio. One of the angles is given, find the value of 'x'.

The correct option is D 50∘ From the diagram, 30∘, 1x and 2x all lie on one the same side of the 'line 2', So, sum of all three angles is 180∘ or, 30∘ +x +2x = 180∘ or, 3x = 150∘ or, x = 50∘

The correct option is D
$50^{\circ}$

From the diagram, $30^{\circ}$ , 1x and 2x all lie on one the same side of the 'line 2',

So, sum of all three angles is $180^{\circ}$

or, $30^{\circ}$ +x +2x = $180^{\circ}$

or, 3x = $150^{\circ}$

or, x = $50^{\circ}$