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Question

Two lines passing through the point (2, 3) intersects each other at an angle of 60°. If slope of one line is 2, find equation of the other line.

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Solution

The two lines are passes through the point ( 2,3 ) and intersect each other at an angle of 60° .

The slope of one of the line is 2 .

Let the slope of another line is m 2 .

The formula for the angle θ between two lines having slopes m 1 and m 2 is given by,

tanθ=| m 1 m 2 1+ m 1 m 2 | (1)

Substitute the values of θ m 1 , m 2 as 60° , 2 and m 2 in equation (1).

tan60°=| 2 m 2 1+2× m 2 | 3 =| 2 m 2 1+2 m 2 | 3 =±( 2 m 2 1+2 m 2 )

If the mod opens with the positive sign then,

3 = 2 m 2 1+2 m 2 3 ( 1+2 m 2 )=2 m 2 3 +2 3 m 2 =2 m 2 2 3 m 2 + m 2 =2 3

Further simplify the above equation.

( 2 3 +1 ) m 2 =2 3 m 2 = 2 3 ( 2 3 +1 )

The formula for the equation of the line having slope m passes through the point ( x 1 , y 1 ) is given by,

( y y 1 )=m( x x 1 ) (2)

Substitute the values of m as 2 3 ( 2 3 +1 ) and ( x 1 , y 1 ) as ( 2,3 ) in equation (2).

( y3 )= 2 3 ( 2 3 +1 ) ( x2 ) ( 2 3 +1 )( y3 )=( 2 3 )( x2 ) ( 2 3 +1 )y6 3 3=( 2 3 )x4+2 3 ( 2 3 +1 )y=( 2 3 )x4+2 3 +6 3 +3

Further simplify the above expression.

( 2 3 +1 )y=( 2 3 )x1+8 3 ( 2 3 )x+( 2 3 +1 )y=1+8 3 ( 3 2 )x+( 2 3 +1 )y=1+8 3

If the mod opens with the negative sign then,

3 =( 2 m 2 1+2 m 2 ) 3 ( 1+2 m 2 )=( 2 m 2 ) 3 +2 3 m 2 = m 2 2 2 3 m 2 m 2 =2 3

Further simplify the above equation.

( 2 3 1 ) m 2 =( 2+ 3 ) m 2 = ( 2+ 3 ) ( 2 3 1 )

Substitute the values of m as ( 2+ 3 ) ( 2 3 1 ) and ( x 1 , y 1 ) as ( 2,3 ) in equation (2).

( y3 )= ( 2+ 3 ) ( 2 3 1 ) ( x2 ) ( 2 3 1 )( y3 )=( 2+ 3 )( x2 ) ( 2 3 1 )y6 3 +3=( 2+ 3 )x+4+2 3 ( 2 3 +1 )y=( 2+ 3 )x+4+2 3 +6 3 3

Further simplify the above expression.

( 2 3 +1 )y=( 2+ 3 )x+1+8 3 ( 2+ 3 )x+( 2 3 +1 )y=1+8 3

Thus the equation of two lines passes through the point ( 2,3 ) and intersect each other at an angle of 60° is ( 3 2 )x+( 2 3 +1 )y=1+8 3 and ( 2+ 3 )x+( 2 3 +1 )y=1+8 3 .


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