Two lines PQ and LM intersect each other at a point O. Now, if the sum of ∠QOL and ∠MOP is 280o, then ∠MOQ will be equal to
40o
∠QOL = ∠MOP (vertically opposite angles are equal)
∠QOL + ∠MOP =280o
Hence ∠MOP = 140o.
∠MOP + ∠MOQ = 180o (linear pair)
Substituting the value of ∠MOP
∠MOQ = 40o