Question

Two liquid drops have their diameters as $1mm$ and $2mm$. The ratio of excess pressures in them is :

• A. $1:2$
• B. $2:1$
• C. $4:1$
• D. $1:4$

Answer 1

Answer: (B)

$2:1$

Excess pressure inside a liquid drop of radius $r$ is

$\Delta P=\frac{2T}{r}$

Thus the ratio of the pressure=$\frac{\Delta P_1}{\Delta P_2}=\frac{r_2}{r_1}=\frac{2}{1}$

Option B is correct.