Two liquid with masses m 1-10 kg and m 2-20 kg are thoroughly mixed- If there specific heats are C 1-0-2 cal - g - - C and C 2- 0-1 cal - g - C and their temperatures are 30- C and 40- C respectively- then the temperature of the mixture is A- 30- CB- 28- CC- 25- CD- 35- C

Name: NEET - 11 - Physics - Thermometry - Session 02 - W15
Uploaded: 2022-07-04T10:36:42+05:30
Description: We know, Temperature of mixture T_mix=m_1C_1T_1+m_2C_2T_2m_1C_1+m_2C_2 =10× 0.2× 30+20× 0.1× 4010× 0.2+20× 0.1 =35^∘C ...

We know, Temperature of mixture T_mix=m_1C_1T_1+m_2C_2T_2m_1C_1+m_2C_2 =10× 0.2× 30+20× 0.1× 4010× 0.2+20× 0.1 =35^∘C ...

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Standard XII

Physics

Specific Heat Capacity

Two liquid wi...

Question

Two liquid with masses $m_{1} = 10 kg$ and $m_{2} = 20 kg$ are thoroughly mixed. If there specific heats are $C_{1} = 0.2 {cal/g -}^{\circ} C$ and $C_{2} = 0.1 {cal/g -}^{\circ} C$ and their temperatures are $30^{\circ} C$ and $40^{\circ} C$ respectively, then the temperature of the mixture is

25^{\circ} C

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35^{\circ} C

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30^{\circ} C

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28^{\circ} C

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Solution

The correct option is B $35^{\circ} C$
We know,
Temperature of mixture
$T_{mix} = \frac{m_{1} C_{1} T_{1} + m_{2} C_{2} T_{2}}{m_{1} C_{1} + m_{2} C_{2}}$

$= \frac{10 \times 0.2 \times 30 + 20 \times 0.1 \times 40}{10 \times 0.2 + 20 \times 0.1}$

$= 35^{\circ} C$

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Specific Heat Capacity

Standard XII Physics

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Two liquid with masses m1=10 kg and m2=20 kg are thoroughly mixed. If there specific heats are C1=0.2 cal/g -∘C and C2=0.1 cal/g -∘C and their temperatures are 30∘C and 40∘C respectively, then the temperature of the mixture is

The correct option is B 35∘C We know, Temperature of mixture Tmix=m1C1T1+m2C2T2m1C1+m2C2 =10×0.2×30+20×0.1×4010×0.2+20×0.1 =35∘C

Two liquid with masses $m_{1} = 10 kg$ and $m_{2} = 20 kg$ are thoroughly mixed. If there specific heats are $C_{1} = 0.2 {cal/g -}^{\circ} C$ and $C_{2} = 0.1 {cal/g -}^{\circ} C$ and their temperatures are $30^{\circ} C$ and $40^{\circ} C$ respectively, then the temperature of the mixture is

The correct option is B $35^{\circ} C$
We know,
Temperature of mixture
$T_{mix} = \frac{m_{1} C_{1} T_{1} + m_{2} C_{2} T_{2}}{m_{1} C_{1} + m_{2} C_{2}}$

$= \frac{10 \times 0.2 \times 30 + 20 \times 0.1 \times 40}{10 \times 0.2 + 20 \times 0.1}$

$= 35^{\circ} C$