Question

Two liquids $A$ and $B$ are at ${30}^{\circ }C$ and ${20}^{\circ }C$, respectively. When they are mixed in equal masses, the temperature of the mixture is found to be ${26}^{\circ }C$. The ratio of their specific heat is

• A. $2:3$
• B. $4:3$
• C. $3:4$
• D. $3:2$

Answer 1

The correct option is D $3:2$

Formula used: $Q=ms\Delta T$
Given: $m_A=m_B=m,T_A={30}^{\circ }C,T_B={20}^{\circ }C,T_f={26}^{\circ }C$
Specific heat of liquid $A$ is $s_A$ and specific heat of liquid $B$ is $s_B$.

Heat lost by body $A$ is equal to heat absorbed by body $B$,
$m{s}_A(30-26)=m{s}_B(26-20)$,\
$\frac{s_A}{s_B}=\frac{6}{4}=\frac{3}{2}$

FINAL ANSWER: (d).