Two liquids A and B are at 30oC and 20oC respectively. When they are mixed in equal masses, the temperature of the mixture is found to be 26oC. The ratio of specific heat is :
A
4 : 3
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B
3 : 4
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C
2 : 3
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D
3 : 2
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Solution
The correct option is D 3 : 2 Loss in temperature of one liquid is equal to the gain in temperature of another liquid. m1.C1.ΔT1=m2.C2.ΔT2 Given the masses are same C1.(30−26)=C2.(26−20) c1c2=64=3/2