Two liquids $A$ and $B$ boils at $145^{o} C$ and $190^{o} C$ . Which of them has higher vapour pressure at $80^{o} C$ ?

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Solution

Vapour pressure correlates with boiling point inversely. In this case liquid A has a lower boiling point and thus will have higher vapour pressure. Since liquid A has a lower boiling point you can assume that its inter-molecular forces are weaker. Therefore, it is much more likely to become a vapour at lower temperatures and more vapour means more pressure.

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Similar questions

145^{o} C

190^{o} C

80^{o} C

Two liquids x and y boil at 110 degrees and 130 degrees Celsius respectively. Which one of them has higher vapour pressure at 50 degree Celsius? Why?

80^{o} C, 60^{o} C, 90^{o} C

100^{o} C

80^{o} C

A

520 m m H g

B

1000 m m H g

A

B

80^{o} C

A

1 a t m = 760 m m H g

Liquid a has higher vapour pressure than liquid b. Which liquid out of a and b will have lower boiling point.

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