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Question

Two liquids A and B form an ideal solution at temperature T. When the total vapour pressure above the solution if 600 torr, the amount fraction of A in the vapour phase is 0.40 and in the liquid phase is 0.6. What are the vapour pressure of pure A and B at temperature T?

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Solution

Let PA be vapour pressure of pure A at temperature T.
Fraction of A in vapour phase=PAPtotal
Let xA be mole fraction of A in liquid phase.
0.4=xA×PAPtotal=0.6×PA600
PA=400Torr
Also, Ptotal=PAxA+PBxB
600=400×0.6+PB×(10.6)
PB=6002400.4=900Torr
Hence, PA=400Torr,PB=900Torr

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