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Standard XII

Physics

Specific Heat Capacity

Two liquids a...

Question

Two liquids are at temperature $20^{\circ} C$ and $40^{\circ} C$ . When same mass of both of them is mixed, the temperature of the mixture is $32^{\circ} C$ . What is the ratio of their specific heats?

\frac{1}{3}

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\frac{2}{5}

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\frac{3}{4}

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\frac{2}{3}

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Solution

The correct option is D $\frac{2}{3}$
$m s_{1} \times (40 - 20) = m s_{2} \times (40 - 32)$
$m s_{1} \times 12 = m s_{2} \times 8$
$\Rightarrow s_{1} ∶ s_{2} = 2 ∶ 3$

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Similar questions

Q. Two liquids are temperature

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Two liquids are at temperature 20∘C and 40∘C. When same mass of both of them is mixed, the temperature of the mixture is 32∘C. What is the ratio of their specific heats?

The correct option is D 23ms1×(40−20)=ms2×(40−32) ms1×12=ms2×8 ⇒s1∶s2=2∶3

Two liquids are at temperature $20^{\circ} C$ and $40^{\circ} C$ . When same mass of both of them is mixed, the temperature of the mixture is $32^{\circ} C$ . What is the ratio of their specific heats?

The correct option is D $\frac{2}{3}$
$m s_{1} \times (40 - 20) = m s_{2} \times (40 - 32)$
$m s_{1} \times 12 = m s_{2} \times 8$
$\Rightarrow s_{1} ∶ s_{2} = 2 ∶ 3$