Two loads of $40$ kgwt and $60$ kgwt sit either end of see-saw of length $3$ m which is supported at its center. The third load of $30$ kgwt should be placed at ____ m from $40$ kgwt so as to balance the see-saw?

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Solution

The correct option is B $0.5$
Let 30 kgwt should be placed at $x m$ from $40 k g w t$ so as to balance the see-saw.
Since the see-saw is balance, net torque shold be zero.
$\Rightarrow τ = 60 g (1.5) - 40 g (1.5) - 30 g (1.5 - x)$
$\Rightarrow 20 g (1.5) = 30 g (1.5 - x)$
$\Rightarrow 3 = 3 (1.5 - x)$
$\Rightarrow x = 0.5 m$
Therefore, B is correct option.

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Two loads of 40 kgwt and 60 kgwt sit either end of see-saw of length 3 m which is supported at its center. The third load of 30 kgwt should be placed at ____ m from 40 kgwt so as to balance the see-saw?

The correct option is B 0.5Let 3030 kgwt should be placed at xm from 40kgwt so as to balance the see-saw.Since the see-saw is balance, net torque shold be zero.⇒τ=60g(1.5)−40g(1.5)−30g(1.5−x)⇒20g(1.5)=30g(1.5−x)⇒3=3(1.5−x)⇒x=0.5mTherefore, B is correct option.

Two loads of $40$ kgwt and $60$ kgwt sit either end of see-saw of length $3$ m which is supported at its center. The third load of $30$ kgwt should be placed at ____ m from $40$ kgwt so as to balance the see-saw?